Photons and the black holes

Of course, photons do not become heavy and does not hit you down. That is because as the theorists explain, the mass of photon at rest is supposedly zero!

So when the photon is having a zero mass, the equation we saw earlier would have a zero in the numerator and therefore, there is no mass to it even while travelling.

Or should we say it becomes an indeterminate, a zero / zero!

Well, let us leave aside Einsteinian Photon for a moment and get back to Newton. If as the theorists say, photon has zero mass. Then according to Newton's gravitational law, the force of gravity between any two objects is proportional to their masses.

Force of gravity = G x m1 x m2 / square of r where G is gravitational constant, m1 and m2 are masses of the objects and r is the distance between them.

So, when light tries to escape from, let us say a black hole, the mass of the photon is zero while that of the black hole is very huge! 

Theorists again say, black hole is black because light is unable to escape from a black hole due to its huge gravitational pull.

If photon has zero mass (m1 in the formula), then the gravitational pull on a photon has to be zero.

If this is the case, then light cannot be withheld by the black hole and therefore, light should emanate out of the black hole or in other words, black hole cannot be black!

But that again, is not what is happening!

What is wrong here? Comments please!

What is a Logical Fallacy?

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